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The Sabbath Rest Of Christ - Spiritual Israel Is His Body

Please read these very important verses - especially after reading the previous page.

-- Click To Expand/Collapse Bible Verses -- Matt ch25:v31-46

Mat 25:31 When the Son of man shall come in his glory, and all the holy angels with him, then shall he sit upon the throne of his glory:
Mat 25:32 And before him shall be gathered all nations: and he shall separate them one from another, as a shepherd divideth  his sheep from the goats:
Mat 25:33 And he shall set the sheep on his right hand, but the goats on the left.
Mat 25:34 Then shall the King say unto them on his right hand, Come, ye blessed of my Father, inherit the kingdom prepared for you from the foundation of the world:
Mat 25:35 For I was hungry, and ye gave me meat: I was thirsty, and ye gave me drink: I was a stranger, and ye took me in:
Mat 25:36 Naked, and ye clothed me: I was sick, and ye visited me: I was in prison, and ye came unto me.
Mat 25:37 Then shall the righteous answer him, saying, Lord, when saw we thee hungry, and fed  thee ? or thirsty, and gave  thee  drink?
Mat 25:38  When saw we thee a stranger, and took  thee  in? or naked, and clothed  thee ?
Mat 25:39 Or when saw we thee sick, or in prison, and came unto thee?
Mat 25:40 And the King shall answer and say unto them, Verily I say unto you, Inasmuch as ye have done  it  unto one of the least of these my brethren, ye have done  it  unto me.
Mat 25:41 Then shall he say also unto them on the left hand, Depart from me, ye cursed, into everlasting fire, prepared for the devil and his angels:
Mat 25:42 For I was hungry, and ye gave me no meat: I was thirsty, and ye gave me no drink:
Mat 25:43 I was a stranger, and ye took me not in: naked, and ye clothed me not: sick, and in prison, and ye visited me not.
Mat 25:44 Then shall they also answer him, saying, Lord, when saw we thee hungry, or athirst, or a stranger, or naked, or sick, or in prison, and did not minister unto thee?
Mat 25:45 Then shall he answer them, saying, Verily I say unto you, Inasmuch as ye did  it not to one of the least of these, ye did  it not to me.
Mat 25:46 And these shall go away into everlasting punishment: but the righteous into life eternal.

The book of revelation tells of the second coming of Christ - how he will reign on earth for a thousand years with His saints whilst the devil is imprisoned in the bottomless pit. We have seen the the identity of the right hand corresponds to a single K4 subgroup that in turn corresponds each of the subgroups of the octal to just one multiplicative element out of seven. That there are six other subgroups shows that the remnant of true spiritual Israel (the 144,000) finds rest in the sabbath reign of Christ's patience for a figurative 1000 years (cycles of the octal). The 144,000 saints in the book of revelation are not just sealed with the Holy Spirit - but are Christ's body.

Were we not to associate groups of subgroups to their intersection (a singleton element) we would have an infinite descent of complexity into groups of groups of groups of groups of.... The intersection allows us to associate in alignment singleton elements to groups of subgroups, but not directly to right handed subgroups in the octal formed of those singletons - the structure is reversed and there is no direct correspondence or alignment.

However by making the cosets of those right hand subgroups into triples by excluding the choice of unity and acting upon the remaining triple with the same seven cycle as in the right hand we actually find an alignment in these triples under the same subgroup-addition of (A v B)c.

So if a= 1 and [b,d,f] is static we find an alignment of the right handed octal singletons upon left handed triples, with multiplication cycling {c,e,g} (corresponding to a = 1 and static under frobenius). through what is in effect a separate "left handed" octal defined on sets of triples rather than on the elements in them. (We would need to define a second octal in that case.)

Now, we may also make these left handed triples into groups of triples, and take the intersection happily enough, but groups of these triples not correspond to our right handed subgroups of our first octal. We can travel from right hand singletons to left handed triples and associate right handed subgroups to groups of right handed triples. The difference being that although the same problem of infinite descent arises for left and right hands separately, now we may associate right handed subgroups to a left handed triple by virtue of the octal that contains them both (and is under the same multiplication.) In essence, the problem of infinite descent will not arise through the direct correspondence of the right handed subgroups to the left handed triples, which circumvents the infinite descent.


The right hand then in which Christ sits as a static K4 subgroup we associate with the 24 elders corresponding to a choice of unity in the Father under the Holy Spirit - (eight possible multiplications with three automorphisms each) and the wider set of 144 sealed states in the other six choices of unity.

Christ as the static subgroup then does not contain this unity element, yet the sabbath rest found in Christ is as an identity element of the octal, found in the intersection of three subgroups that span the octal, say a = 1 and [a,b,c],[a,d,e],[a,f,g]. These three subgroups correspond to left handed singletons, say c,e,g respectively. Then {c,e,g} corresponds directly to 'a' and therefore map to the static subgroup [b,d,f] of the right hand.

Clearly, Jesus separates out His elect (His sheep) to His right hand and the goats out to His left. In order to find a rest state of unity one can perform the reverse, and state that someone MUST dwell in a K4 subgroup of the right hand (at the end of the argument) to have been separated from those remaining in the left hand that would claim to have the proper rest of unity in the octal.

Jesus taught that whosoever has the Son has the Father, but those without the Son do not have the Father at all. The Father, in terms here are the Holy Spirit, the elements of the right hand octal's seven cycle, and the right handed elements or subgroups of the right handed octal. Clearly by definition a person can agree with the position of the unity element, the proposed rest of Christ - yet if the person merely dwells in the left hand coset of the group in Christ, ({c,e,g} as opposed to [b,d,f] here) They do not have the right handed octal (or its operation) unless they are translated spiritually to the static subgroup where Christ is sat at the right hand, [b,d,f]. Remaining in {c,e,g} is not salvation, being found in Christ by translation in the octal from without the (subgroup) fold, i.e. outside in {c,e,g} to within the fold i.e. in [b,d,f] is what is necessary for salvation.

As I am so fond of hearing, it doesn't matter if you know Christ, the question is, "Does Christ know you?"


There is no structure in the octal to place the unity element inside the static subgroup. Although this would result in an alignment as such, under say (a,b,d,c,f,g,e);

a = 1 = [a,b,c]
b = [b,d,f]
d = [c,d,g]
c = [c,e,f]
f = [a,f,g]
g = [b,e,g]
e = [a,d,e]

There is no alignment of octal structure here, neither is there the possibility of structure in the field GF(8). There is one structure we may use however, the alternative K4 form of the ultrafilter;

a = 1 = [a,b,c]
b = [a,d,e]
c = [a,f,g]

This has its form from the element a = 1 from the octal and the induced 3-cycle under frobenius that sends {c,e,g} and [b,d,f] to themselves. The result is that [a,b,c],[a,d,e],[a,f,g] form a K4 group and a cyclic group under that frobenius map.

In the octal itself the only valid associations are along the lines of;

e = [a,b,c] with a = 1 and [b,d,f] static
g = [a,d,e]
c = [a,f,g]

Likewise again we see from the correspondence that a believer must be translated from {c,e,g} to [a,b,c], though this translation is done in the K4 ultrafilter apart from the octal, and not in the octal itself. The K4 form of a = 1 = [a,b,c] is stable on its own when apart from the octal ultrafilter, and we may now state that being in Christ is also stable, and not a result of continuous translation and effort by God from {c,e,g} to [b,d,f] - rather the translation is from {c,e,g} to [a,b,c] = 1 in Christ (as the K4 form) and from unity in the intersection of GF(4) and GF(8) as separate finite fields to stability found as [b,d,f] in the octal that corresponds to unity in Christ: It is In Christ, and through Christ that a person inherits the Father's rest.


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